7x^2-62=1+

Solution for 7x^2-62=1+ equation:

7x^2-62=1+

We move all terms to the left:

7x^2-62-(1+)=0

We add all the numbers together, and all the variables

7x^2-62-0=0

We add all the numbers together, and all the variables

7x^2-62=0

a = 7; b = 0; c = -62;
Δ = b2-4ac
Δ = 02-4·7·(-62)
Δ = 1736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1736}=\sqrt{4*434}=\sqrt{4}*\sqrt{434}=2\sqrt{434}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{434}}{2*7}=\frac{0-2\sqrt{434}}{14}
=-\frac{2\sqrt{434}}{14}
=-\frac{\sqrt{434}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{434}}{2*7}=\frac{0+2\sqrt{434}}{14}
=\frac{2\sqrt{434}}{14}
=\frac{\sqrt{434}}{7}
$